9x^2+28x-37=0

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Solution for 9x^2+28x-37=0 equation:



9x^2+28x-37=0
a = 9; b = 28; c = -37;
Δ = b2-4ac
Δ = 282-4·9·(-37)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-46}{2*9}=\frac{-74}{18} =-4+1/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+46}{2*9}=\frac{18}{18} =1 $

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